Saturday, December 14, 2013

Title: Conservation of Energy Lab Purpose: To verify that the total energy of an object doesn't change if the object hasn't done work.

Title: Conservation of Energy Lab Purpose: To cast that the total energy of an physical mark doesnt change if the aspiration hasnt done work. Procedure: 1. Attach a motion-picture show approach to the bottom of the thermionic piping that is attached to a erect metal rod. 2. Attach the film entrance to the computer, and open mackintosh Motion. 3. Record all measurements, tube to ground, tube to photo logic gate. 4. Go get a abject subdivision of premature ventricular contraction grouse that will be dropped with the tube 5. Measure two heap and length of the small get together of polyvinyl chloride shriek. 6. Drop the small region of PVC pipe through the long piece of pipe and through the photo gate 7. Record the amount of succession it took for the small piece of PVC pipe to reap by the photo gate. Data: pg = photo gate Small piece of PVC pipe plenty: .0116kg Small piece of PVC pipe length: .058m continuance from the authorize of the tube to the ground = 1.867m Distance from the photo gate to the ground. = .266 m Trial #Time for the object to pass through the (pg) 1.0115s 2.0116s 3.0118s Calculations: TE = Total Energy PE = Potential Energy KE = energising Energy m = mass g = gravity = 9.81N/kg h = height Calculating the TE of the small piece of PVC pipe at the go across of the tube before we dropped it. PE=mgh=(.0116kg)(9.81N/kg)(1.876m)=0.212J KE=1/2mv=0J TE=PE+KE=0.212J+0J=0.
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212J Calculating the Average further of the object as it passes through the photo gate. .0115s+.0116s+.0118s ------------------------------- = .0116s 3 .058m/.0116s ------------ ------- = 5m/s .0116 Calculating the ! TE of the small piece of PVC pipe as it passes through the photo gate. PE=mgh=(.0116kg)(9.81N/kg)(.266m)=0.030J KE=1/2mv=1/2(.0116kg)(5m/s)=0.145J TE=PE+KE=0.175J Calculating the difference in TE between the crimp of the tube and the photo gate .212J-.175J=.037J .175J -------- =... If you want to get a climb essay, order it on our website: BestEssayCheap.com

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