Quadratic Equations

Week 3 Assignment ZyAlicia Olvera Mat 126 Instructor Laura Cella Sep.10, 2012 theatrical role 1: Using the interesting method to act upon quadratic comparison comparabilitys from India. personally I did not find this method every little confusing than the other methods I confuse lettered about, I am not even sure I have a good understanding of this math, or quadratic equations. A) x2-2x-13=0 hightail it the constant bound to the duty human face of the equation: x2-2x=13 figure severally term by four times the coefficient of x2 -42x=413 or 4x2-8x=52 Square the coefficient of the x term and add to twain slopes of the equation: 4x2-8x+4=52+4 or 4x2-8x+4=56 bring in the material ticktack-go of both spatial relations: (4x2-8x+4) = 56 or, (2x-2)2 = 56 or, 2x-2= 56 e.

2x-2= +56 go down left side represent to confirming self-colored topic of right side and solve for x: x= (2+56)2 2x-2= -56 Set left side equal to ban foursquare root of right side and solve for x: So: x= (2+56)2 x=116 or x= (2-56)2 x=-108 C) x2 +12x-64= 0 give out the constant term to right side of equation x2 +12x=64 Multiply each term by four times coefficient of x2 4x+ 4 12x= 4 64 or, 4x2+48x=256 Square the coefficient of x term and add to both sides of equation 4x2+48x+144=256+144 or, 4x2+48x+144=400 Take square root of both sides 4x2+48x+144 = 400 or, (2x+12)2 = 400 or, 2x+12= 20 or, 2x+12= +20 Set left side equal to positive square root of right side and solve for x x= (-12+20)2= 4 2x+12= -20 Set left side equal to negative square root of right side and solve for x x= (-12-20)2= -16 x=4 or x=-16 Part 2: experiment to find a tou! r for x that when substituted in the shape yields a composite number. x = 0 02-0+41=41 41 is a indigenous number x = 2 22-2+41= 4-2+41= 2+41=43 43 is a salad days number x = 5 52-5+41= 25-5+41 20+41=61 61 is a gear up number x=6 62-6+41= 36-6+41= 30+41=71 71 is a prime number x= 7 72-7+41= 49-7+41= 42+41=83 83 is a prime number x=22 222-22+41= 484-22=462 462+41=503 503 is a prime number x = 41 412-41+41=...If you essential to get a full essay, order it on our website: BestEssayCheap.com

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